A) 36 \[c{{m}^{2}}\]
B) 40 \[c{{m}^{2}}\]
C) 44 \[c{{m}^{2}}\]
D) 50 \[c{{m}^{2}}\]
Correct Answer: B
Solution :
(b): Volume \[=4\times 2\times \frac{\left( 6+4 \right)}{2}=40\]\[c{{m}^{3}}\]
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