A) 9 m
B) 24 m
C) 12 m
D) 60 m
Correct Answer: A
Solution :
(a): Given that, Radius of sphere \[(r)=3cm=0.03\] m Radius of wire \[=0.2\] \[\Rightarrow R=0.2cm=0.002\]m Given condition, Volume of sphere=Volume of wire \[\Rightarrow \frac{4}{3}\pi {{r}^{3}}=\pi {{R}^{2}}h\] \[\therefore h=\frac{4}{3}.\frac{{{r}^{3}}}{{{R}^{2}}}\] \[=\frac{4}{3}\times \frac{0.03\times 0.03\times 0.03}{0.002\times 0.002}=9\]cm
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