A) \[\frac{\pi }{2}\]
B) \[\frac{\pi }{4}\]
C) \[-\frac{\pi }{2}\]
D) None of these
Correct Answer: C
Solution :
\[\int_{-1}^{1}{\frac{d}{dx}}\left( {{\tan }^{-1}}\frac{1}{x} \right)\,dx=-2[{{\tan }^{-1}}(x)]_{0}^{1}=-\frac{\pi }{2}\].
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