A) \[C{{H}_{3}}CH=CHC{{H}_{3}}\]
B) \[{{(C{{H}_{3}})}_{2}}C=C\,{{(C{{H}_{3}})}_{2}}\]
C) \[{{N}_{2}}O.FeS{{O}_{4}}\]
D) \[C{{H}_{3}}-CH=C\,{{(C{{H}_{3}})}_{2}}\]
Correct Answer: A
Solution :
and
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