A) \[\begin{matrix} \ \ \ \ H \\ {{H}_{3}}C \\ \end{matrix}>C=C<\begin{matrix} H\ \ \ \\ C{{H}_{3}} \\ \end{matrix}\]
B) \[\begin{matrix} {{C}_{2}}H \\ \,\,\,\ H \\ \end{matrix}>C=C<\begin{matrix} H \\ H \\ \end{matrix}\]
C) \[\begin{matrix} C{{H}_{3}} \\ C{{H}_{3}} \\ \end{matrix}>C=C<\begin{matrix} H \\ H \\ \end{matrix}\]
D) \[H-\overset{C{{H}_{3}}}{\mathop{\underset{H}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}\,\ -}}\,\underset{H}{\mathop{\underset{|}{\mathop{C}}\,}}\,=C<\begin{matrix} H \\ H \\ \end{matrix}\]
Correct Answer: A
Solution :
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