A) \[1.067\,\tau \]
B) \[1.143\,\tau \]
C) \[1.333\,\tau \]
D) \[2\,\tau \]
Correct Answer: A
Solution :
\[{{\tau }_{s}}=\frac{16T}{\pi {{D}^{3}}}\] \[{{\tau }_{h}}=\frac{16T}{\pi {{D}^{2}}(1-{{k}^{4}})}=\frac{16T}{\pi {{D}^{3}}\left( 1-\frac{1}{16} \right)}=\frac{16}{15}{{\tau }_{s}}\] \[=1.067\tau \]
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