A) 0.44 \[\delta \]
B) 0.67 \[\delta \]
C) 1.5 \[\delta \]
D) 2.25 \[\delta \]
Correct Answer: D
Solution :
Mid-span deflection of a simply supported beam carrying concentrated load at the centre, \[\delta =\frac{W{{L}^{3}}}{48El}\] \[\delta \propto \frac{1}{l}\] \[\frac{{{\delta }_{2}}}{{{\delta }_{_{1}}}}=\frac{{{I}_{1}}}{{{I}_{2}}}\] \[\frac{{{\delta }_{2}}}{{{\delta }_{_{1}}}}=\frac{\left( \frac{4\times {{6}^{2}}}{12} \right)}{\left( \frac{6\times {{4}^{2}}}{12} \right)}={{\left( \frac{6}{4} \right)}^{2}}\] \[{{\delta }_{2}}=2.25\delta \]
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