A) \[-a\cos (kx+\omega t)\]
B) \[a\cos (kx-\omega t)\]
C) \[-a\cos (kx-\omega t)\]
D) \[-a\sin (kx+\omega t)\]
Correct Answer: C
Solution :
\[a\cos (kx+\omega \,t)\] hence \[{{y}_{\text{reflected}}}=a\cos (-kx+\omega \,t+\pi )=-a\cos (kx-\omega \,t)\]
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