JEE Main & Advanced Physics Electro Magnetic Induction Question Bank Static EMI

  • question_answer
    Two coils A and B having turns 300 and 600 respectively are placed near each other, on passing a current of 3.0 ampere in A, the flux linked with A is \[1.2\times {{10}^{-4}}\,weber\] and with B it is \[9.0\times {{10}^{-5}}\,weber\]. The mutual inductance of the system is                                                                         [MP PMT 2001]

    A) \[2\times {{10}^{-5}}\,henry\]           

    B) \[3\times {{10}^{-5}}\,henry\]

    C) \[4\times {{10}^{-5}}\,henry\]             

    D) \[6\times {{10}^{-5}}\,henry\]

    Correct Answer: B

    Solution :

    \[{{N}_{2}}{{\varphi }_{2}}=M{{i}_{1}}\Rightarrow 9\times {{10}^{-5}}=M\times 3\] \[\Rightarrow M=3\times {{10}^{-5}}H\]


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