A) 2 H
B) 5 H
C) 20 H
D) 10 H
Correct Answer: D
Solution :
\[N\varphi =Li\Rightarrow \frac{Nd\varphi }{dt}=\frac{Ldi}{dt}\Rightarrow NB\frac{dA}{dt}=\frac{Ldi}{dt}\] \[\Rightarrow \frac{1\times 1\times 5}{{{10}^{-3}}}=L\times \left( \frac{2-1}{2\times {{10}^{-3}}} \right)\Rightarrow L=10H\]
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