JEE Main & Advanced Physics Electro Magnetic Induction Question Bank Static EMI

  • question_answer
    A 100 mH coil carries a current of 1 ampere. Energy stored in its magnetic field is                [CBSE PMT 1992; KCET 1998]

    A)            0.5 J                                         

    B)            1 J

    C)            0.05 J                                       

    D)            0.1 J

    Correct Answer: C

    Solution :

               Energy \[=\frac{1}{2}L{{I}^{2}}=\frac{1}{2}\times 100\times {{10}^{-3}}\times {{1}^{2}}=0.05J\]


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