A) 1 millihenry
B) 10 millihenry
C) 100 millihenry
D) 1000 millihenry
Correct Answer: A
Solution :
Induced \[e.m.f.\ \ e=M\frac{di}{dt}\Rightarrow 100\times {{10}^{-3}}=M\left( \frac{10}{0.1} \right)\] \[\therefore \ M={{10}^{-3}}H=1\ mH\]You need to login to perform this action.
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