JEE Main & Advanced Physics Electro Magnetic Induction Question Bank Static EMI

  • question_answer
    The current flowing in a coil of self inductance 0.4 mH is increased by 250 mA in 0.1 sec. The e.m.f. induced will be [MP PMT 1994]

    A)            + 1 V                                        

    B)            ? 1 V

    C)            + 1 mV                                    

    D)            ? 1 mV

    Correct Answer: D

    Solution :

               \[e=-L\frac{di}{dt}=-0.4\times {{10}^{-3}}\times \frac{250\times {{10}^{-3}}}{0.1}=-1\ mV\]


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