JEE Main & Advanced Physics Electro Magnetic Induction Question Bank Static EMI

  • question_answer
    An e.m.f. of 12 volts is induced in a given coil when the current in it changes at the rate of 48 amperes per minute. The self inductance of the coil is              [MP PMT 2000]

    A)            0.25 henry                             

    B)            15 henry

    C)            1.5 henry                               

    D)            9.6 henry

    Correct Answer: B

    Solution :

               \[L=\frac{e}{di/dt}=\frac{12}{48/60}=15\ H\]


You need to login to perform this action.
You will be redirected in 3 sec spinner