JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Static and Limiting Friction

  • question_answer
    The coefficient of static friction, \[{{\mu }_{s}},\] between block A of mass 2 kg and the table as shown in the figure is 0.2. What would be the maximum mass value of block B so that the two blocks do not move? The string and the pulley are assumed to be smooth and massless. \[(g=10\,m/{{s}^{2}})\]    [CBSE PMT 2004]

    A)                         2.0 kg              

    B)                         4.0 kg            

    C)  0.2 kg 

    D)  0.4 kg

    Correct Answer: D

    Solution :

                    \[{{\mu }_{s}}=\frac{{{m}_{B}}}{{{m}_{A}}}\] Þ \[0.2=\frac{{{m}_{B}}}{2}\] Þ\[{{m}_{B}}=0.4\ kg\]


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