JEE Main & Advanced Mathematics Determinants & Matrices Question Bank Special types of matrices, Transpose, Adjoint and Inverse of matrices

  • question_answer
    The adjoint of \[\left[ \begin{matrix}    1 & 1 & 1  \\    1 & 2 & -3  \\    2 & -1 & 3  \\ \end{matrix} \right]\]is [RPET 1993]

    A) \[\left[ \begin{matrix}    3 & -9 & -5  \\    -4 & 1 & 3  \\    -5 & 4 & 1  \\ \end{matrix} \right]\]

    B) \[\left[ \begin{matrix}    3 & -4 & -5  \\    -9 & 1 & 4  \\    -5 & 3 & 1  \\ \end{matrix} \right]\]

    C) \[\left[ \begin{matrix}    -3 & \,\,4 & 5  \\    9 & -1 & -4  \\    5 & -3 & -1  \\ \end{matrix} \right]\]

    D) None of these

    Correct Answer: B

    Solution :

    Let, \[A=\left[ \begin{matrix}    1 & 1 & 1  \\    1 & 2 & -3  \\    2 & -1 & 3  \\ \end{matrix} \right]\];   \[adj(A)=\left[ \begin{matrix}    {{A}_{11}} & {{A}_{21}} & {{A}_{31}}  \\    {{A}_{12}} & {{A}_{22}} & {{A}_{32}}  \\    {{A}_{13}} & {{A}_{23}} & {{A}_{33}}  \\ \end{matrix} \right]\] \[\Rightarrow \] \[{{A}_{11}}=3,\,\,{{A}_{12}}=-9,\,\,{{A}_{13}}=-5\]               \[{{A}_{21}}=-4,\,{{A}_{22}}=1,\,{{A}_{23}}=3\]        \[{{A}_{31}}=-5,\,{{A}_{32}}=4,\,{{A}_{33}}=1\] \[\Rightarrow \] \[Adj\,(A)=\left[ \begin{matrix}    3 & -4 & -5  \\    -9 & 1 & 4  \\    -5 & 3 & 1  \\ \end{matrix} \right]\].


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