A) \[619{}^\circ C\]
B) \[719{}^\circ C\]
C) \[819{}^\circ C\]
D) \[919{}^\circ C\]
Correct Answer: C
Solution :
\[\frac{{{v}_{t}}}{{{v}_{0}}}=\sqrt{\frac{{{T}_{t}}}{{{T}_{0}}}}\] \[\therefore \] \[\frac{2{{v}_{0}}}{{{v}_{0}}}=\sqrt{\frac{{{T}_{t}}}{273}}\] (since\[{{v}_{t}}=2{{v}_{0}}\]) \[\Rightarrow \] \[4=\frac{{{T}_{t}}}{273}\] \[\Rightarrow \] \[{{T}_{t}}=4\times 273=1092\,\,K\] \[=1092-273={{819}^{o}}C\]
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