9th Class Science Sound Question Bank Sound IIT JEE Subjective Problems

  • question_answer
    The diagram below shows a section of a wave form in a string. The numbers in the diagram show distances in centimeter. The speed of travel of the wave is\[\text{8}00\text{ m}{{\text{s}}^{-\text{1}}}\].
    (i) What is the wavelength? (ii) What is the amplitude? (iii) Calculate the frequency?

    Answer:

    (i) Wavelength is distance between two consecutive or troughs \[=3010=20\text{ }cm.\] (ii) Amplitude is the maximum displacement = 4 cm (iii)We know \[v=n\lambda \]\[\Rightarrow \]\[n=\frac{V}{\lambda }=\frac{800m/s}{20\times {{10}^{-2}}m}=4000Hz\]


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