JEE Main & Advanced Mathematics Trigonometric Equations Question Bank Solution of trigonometrical equations

  • question_answer
    If \[\tan 2\theta \tan \theta =1\], then the general value of\[\theta \]is [Roorkee 1980; Karnataka CET 1992, 93, 2003]

    A) \[\left( n+\frac{1}{2} \right)\frac{\pi }{3}\]

    B) \[\left( n+\frac{1}{2} \right)\,\pi \]

    C) \[\left( 2n\pm \frac{1}{2} \right)\frac{\pi }{3}\]

    D) None of these

    Correct Answer: A

    Solution :

    \[\tan 2\theta =\cot \theta \] Þ \[\tan 2\theta =\tan \text{ }\left( \frac{\pi }{2}-\theta  \right)\] \[\Rightarrow \]  \[2\theta =n\pi +\frac{\pi }{2}-\theta \Rightarrow \theta =\frac{n\pi }{3}+\frac{\pi }{6}\].


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