A) 1, 2 -2
B) \[-2,\frac{2}{3},-\frac{2}{3}\]
C) \[-3,\frac{3}{2},-\frac{3}{2}\]
D) \[-4,\frac{3}{2},-\frac{3}{2}\]
Correct Answer: D
Solution :
Given equation\[4{{x}^{3}}+16{{x}^{2}}-9x-36=0\], Putting \[x=-4\]Þ \[-4\times 64+256+36-36=0\] Hence \[x=-4\] is a root of the equation Now reduced equation is \[4{{x}^{2}}(x+4)-9(x+4)=0\] Þ \[(x+4)(4{{x}^{2}}-9)=0\]Þ \[x=-4,x=\pm \frac{3}{2}\] Thus roots are \[-4\,,-\frac{3}{2},\frac{3}{2}\]You need to login to perform this action.
You will be redirected in
3 sec