A) \[{{x}^{3}}-8=0\]
B) \[{{x}^{3}}-16=0\]
C) \[{{x}^{3}}+64=0\]
D) \[{{x}^{3}}-64=0\]
Correct Answer: D
Solution :
Let\[y={{x}^{2}}\]. Then \[x=\sqrt{y}\] \ \[{{x}^{3}}+8=0\,\,\Rightarrow \,\,{{y}^{3/2}}+8=0\] Þ \[{{y}^{3}}=64\,\,\,\Rightarrow \,\,\,{{y}^{3}}-64=0\] Thus the equation having roots \[{{\alpha }^{2}},{{\beta }^{2}}\] and \[{{\gamma }^{2}}\]is\[{{x}^{3}}-64=0\].You need to login to perform this action.
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