A) \[5,-4,\frac{1\pm 5\sqrt{-3}}{2}\]
B) \[-5,4,-\frac{1\pm 5\sqrt{-}3}{2}\]
C) \[5,4,\frac{-1\pm 5\sqrt{-}3}{2}\]
D) \[-5,-4,\frac{1\pm 5\sqrt{-}3}{2}\]
Correct Answer: A
Solution :
Given equation is \[{{x}^{4}}-2{{x}^{3}}+x-380=0\] Using remainder theorem we get \[(x-5)\,(x+4)({{x}^{2}}-x+19)=0\] \[x-5=0\], \[x-4=0\] and \[{{x}^{2}}-x+19=0\] \[x=5\], \[x=-4\] and\[x=\frac{-1\pm 5\sqrt{-3}}{2}\].
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