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JEE Main & Advanced Mathematics Complex Numbers and Quadratic Equations Question Bank Solution of quadratic inequations and Miscellaneous equations

  • question_answer
    If two roots of the equation \[{{x}^{3}}-3x+2=0\] are same, then the roots will be [MP PET 1985]

    A) 2, 2, 3

    B) 1, 1, -2

    C) - 2, 3, 3

    D) -2, -2, 1

    Correct Answer: B

    Solution :

    Given equation is \[{{x}^{3}}-3x+2=0\] Þ \[{{x}^{2}}(x-1)+x(x-1)-2(x-1)=0\] Þ \[(x-1)({{x}^{2}}+x-2)=0\]Þ \[(x-1)(x-1)(x+2)=0\] Hence roots are \[1,1,-2\]


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