A) \[a=b=0,c\in R\]
B) \[a=c=0,b\in R\]
C) \[{{b}^{2}}-4ac\ge 0\]
D) \[a=b=c=0\]
Correct Answer: D
Solution :
Since quadratic equation \[a{{x}^{2}}+bx+c=0\]has three distinct roots so it must be an identity. So\[a=b=c=0\].
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