A) \[y=0,\ x-y\sqrt{3}=0\]
B) \[x=0,\ x-y\sqrt{3}=0\]
C) \[x=0,\ x+y\sqrt{3}=0\]
D) \[y=0,\ x+y\sqrt{3}=0\]
Correct Answer: B
Solution :
Since the line \[x+y\sqrt{3}+3\sqrt{3}=0\]makes an angle of \[{{150}^{o}}\]with \[x\]-axis. Therefore, the required lines will make angles of \[{{90}^{o}}\]and \[{{210}^{o}}\] i.e., \[{{30}^{o}}\]with the positive direction of x-axis. Hence the lines are \[x=0\] and\[y=\frac{1}{\sqrt{3}}x\].
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