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JEE Main & Advanced Mathematics Straight Line Question Bank Slope of line, Equation of line in different forms

  • question_answer
    The equation of a line through \[(3,\,-4)\] and perpendicular to the line \[3x+4y=5\]is   [RPET 1981, 84, 86; MP PET 1984]

    A)            \[4x+3y=24\]                         

    B)            \[y-4=(x+3)\]

    C)            \[3y-4x=24\]                           

    D)            \[y+4=\frac{4}{3}(x-3)\]

    Correct Answer: D

    Solution :

               The required equation, which passes through (3, ? 4) and its gradient is \[\frac{4}{3}\], is \[(y+4)=\frac{4}{3}(x-3)\].


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