JEE Main & Advanced Physics Simple Harmonic Motion Question Bank Simple Pendulum

  • question_answer
    The bob of a simple pendulum of mass m and total energy E will have maximum linear momentum equal to                                                                                          [MP PMT 1986]

    A)            \[\sqrt{\frac{2E}{m}}\]    

    B)            \[\sqrt{2mE}\]

    C)            \[2mE\]                                  

    D)            \[m{{E}^{2}}\]

    Correct Answer: B

    Solution :

               \[{{p}_{\max }}=\sqrt{2m\,{{E}_{\max }}}\]


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