(i) the equation formed is |
(ii) the number of 1st prizes are |
(iii) the number of 2nd prizes are |
A)
(i) (ii) (iii) \[2500x+1500(40-x)=85000\] 25 15
B)
(i) (ii) (iii) \[2500x-1500(40-x)=85000\] 36 4
C)
(i) (ii) (iii) \[2500x\times 1500(x-40)=85000\] 20 20
D)
(i) (ii) (iii) \[2500x-1500(x-40)=85000\] 15 25
Correct Answer: A
Solution :
Let the number of 1st prizes be x, Then the number of 2nd prizes \[=40-x\] According to the question, \[2500(x)+1500(40-x)=85000\] \[\Rightarrow \] \[2500x+60000-1500x=85000\] \[\Rightarrow \] \[1000x=25000\Rightarrow x=25\] So, number of 1st prizes = 25 Number of 2nd prizes \[=40-25=15\]You need to login to perform this action.
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