A) \[{{10}^{2}}:1\]
B) \[{{10}^{-2}}:1\]
C) \[1:{{10}^{-4}}\]
D) \[1:{{10}^{4}}\]
Correct Answer: D
Solution :
Resistance in forward biasing \[{{R}_{fr}}\approx 10\,\Omega \]and resistance in reverse biasing \[{{R}_{Rw}}\approx {{10}^{5}}\Omega \] Þ \[\frac{{{R}_{fr}}}{{{R}_{Rw}}}=\frac{1}{{{10}^{4}}}\]
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