A) \[y=r\sin \,\omega t\]
B) \[y=r\sin (\omega t-kx)\]
C) \[y=\frac{a}{\sqrt{r}}\sin (\omega t-kx)\]
D) \[y=\frac{a}{r}\sin (\omega t-kr)\]
Correct Answer: B
Solution :
[b] The position of such a wave changes in two dimensional plane with time.
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