A) \[\frac{2{{f}_{0}}v{{v}_{0}}}{{{v}^{2}}+v_{0}^{2}}\]
B) \[\frac{2{{f}_{0}}{{v}^{2}}}{{{v}^{2}}-v_{0}^{2}}\]
C) \[\frac{2{{f}_{0}}v{{v}_{0}}}{{{v}^{2}}-{{v}_{0}}^{2}}\]
D) \[\frac{{{f}_{0}}v{{v}_{0}}}{{{v}^{2}}-{{v}_{0}}^{2}}\]
Correct Answer: C
Solution :
[c] \[{{f}_{2}}=\frac{{{f}_{0}}v}{v+{{v}_{0}}}\] The wave which reaches wall \[{{f}_{1}}\] is reflected. \[{{f}_{1}}=\frac{{{f}_{0}}v}{v-{{v}_{0}}}\] The reflected frequency is \[{{f}_{1}}\]as the wall is at rest. Beats\[={{f}_{1}}-{{f}_{2}}=\frac{{{f}_{0}}v}{v-{{v}_{0}}}-\frac{{{f}_{0}}v}{v+{{v}_{0}}}=\frac{2{{f}_{0}}v{{v}_{0}}}{{{v}^{2}}-{{v}_{0}}^{2}}\]
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