A) 24
B) 14
C) 10
D) none of these
Correct Answer: B
Solution :
[b] \[{{\lambda }_{1}}=50cm.\] \[{{\lambda }_{2}}=51\,cm.\] \[v\propto \sqrt{T}\Rightarrow \frac{{{v}_{1}}}{{{v}_{2}}}=\sqrt{\frac{{{T}_{2}}}{{{T}_{1}}}}=\sqrt{\frac{273+20}{273}}\] \[\Rightarrow \,\,\,{{v}_{2}}=319.23.\] \[{{v}_{1}}=\frac{{{v}_{2}}}{{{\lambda }_{1}}}=\frac{319.23}{0.50}=640Hz\] \[{{v}_{2}}=\frac{{{v}_{2}}}{{{\lambda }_{2}}}=\frac{319.23}{51\times {{10}^{-2}}}=625.94=626Hz.\] No. of beats \[={{v}_{2}}-{{v}_{1}}=14Hz\]
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