A) 105 Hz
B) 1.05 Hz
C) 1050 Hz
D) 10.5 Hz
Correct Answer: A
Solution :
[a] Given \[\frac{nv}{2\ell }=315\,\,and\,(n+1)\frac{v}{2\ell }=420\] \[\Rightarrow \frac{n+1}{n}=\frac{420}{315}\Rightarrow n=3\] Hence\[3\times \frac{v}{2\ell }=315\Rightarrow \frac{v}{2\ell }=105Hz\] The lowest resonant frequency is when n = 1 Therefore lowest resonant frequency = 105Hz.
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