A) 1 kg
B) 2 kg
C) 4 kg
D) 16 kg
Correct Answer: D
Solution :
[d] Load supported by sonometer wire = 4 kg Tension in sonometer wire = 4 g If\[\mu \]= mass per unit length then frequency \[v=\frac{1}{21}\sqrt{\frac{T}{\mu }}\] \[\Rightarrow 416=\frac{1}{21}\sqrt{\frac{4g}{\mu }}\] When length is doubled, i.e., \[l'=2l\] Let new load =L As, \[v'=v\] \[\therefore \,\,\frac{1}{2l'}\sqrt{\frac{Lg}{\mu }}=\frac{1}{2l}\sqrt{\frac{4g}{\mu }}\] \[\Rightarrow \,\frac{1}{4l}\sqrt{\frac{Lg}{\mu }}=\frac{1}{2l}\sqrt{\frac{4g}{\mu }}\] \[\Rightarrow \sqrt{L}=2\times 2\Rightarrow L=16kg\]
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