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JEE Main & Advanced Physics Wave Mechanics Question Bank Self Evaluation Test - Waves

  • question_answer
    The equation of a wave on a string of linear mass density \[0.04kg\,{{m}^{-1}}\] is given by \[y=0.02(m)\sin \left[ 2\pi \left( \frac{1}{0.04(s)}-\frac{x}{0.50(m)} \right) \right]\] The tension in the string is

    A)  4.0 N

    B)  12.5 N

    C) 0.5 N

    D) 6.25 N

    Correct Answer: D

    Solution :

    [d] \[T=\mu \,{{v}^{2}}=\mu \frac{{{\omega }^{2}}}{{{k}^{2}}}=0.04\frac{{{(2\pi /0.004)}^{2}}}{{{(2\pi /0.50)}^{2}}}\] 6.25 N


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