A) 3 : 2 : 1
B) 6 : 3 : 2
C) 6 : 2 : 3
D) 2 : 3 : 6
Correct Answer: B
Solution :
[b] Frequency \[v=\frac{1}{2L}\sqrt{\frac{T}{m}}\] \[\because V\propto \frac{1}{l}\] \[\therefore \,\,{{l}_{1}}:{{l}_{2}}:{{l}_{3}}=\frac{1}{1}:\frac{1}{2}:\frac{1}{3}=6:3:2\]
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