JEE Main & Advanced Physics Wave Mechanics Question Bank Self Evaluation Test - Waves

  • question_answer
    If the length of a stretched string is shortened by 40% and the tension increased by 44% then the ratio of the final and initial fundamental frequencies is            

    A)  3 : 4

    B)  4 : 3 

    C) 1 : 3

    D) 2 : 1

    Correct Answer: D

    Solution :

    [d] \[n=\frac{1}{2\ell }\sqrt{\frac{T}{m}}\therefore \frac{{{n}_{2}}}{{{n}_{1}}}=\frac{{{\ell }_{1}}}{{{\ell }_{2}}}\sqrt{\frac{{{T}_{2}}}{{{T}_{1}}}}\] \[=\frac{{{\ell }_{1}}}{\left[ {{\ell }_{1}}-\frac{40}{100}{{\ell }_{1}} \right]}\frac{\sqrt{{{T}_{1}}+\left( \frac{44}{100} \right)}{{T}_{1}}}{{{T}_{1}}}\] \[=\frac{100}{60}\times \frac{12}{10}=2:1\]


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