question_answer

Tube A has both ends open while tube B has one end closed, otherwise they are identical. The ratio of fundamental frequency of tube A and B is

A)  1 : 2

B)  1 : 4

C) 2 : 1

D) 4 : 1

Correct Answer: C

Solution :

[c] \[\frac{{{\lambda }_{A}}}{{{\lambda }_{B}}}=\frac{1}{2}\Rightarrow \frac{{{n}_{A}}}{{{n}_{B}}}=\frac{2}{1}\]