A) \[-ve\]x direction with frequency 1 Hz.
B) \[+ve\]x direction with frequency n Hz and wavelength \[\lambda =0.2m\].
C) \[+ve\] x direction with frequency 1 Hz and wavelength \[\lambda =0.2m\]
D) \[-ve\] x direction with amplitude 0.25 m and wavelength \[\lambda =0.2m\]
Correct Answer: C
Solution :
[c] \[y=0.25\,\sin (10\pi x-2\pi t)\] Comparing this equation with the standard wave equation \[y=a\,\sin (kx-\omega t)\] We get. \[k=10\pi \Rightarrow \frac{2\pi }{\lambda }=10\pi \Rightarrow \lambda =0.2m\] And \[\omega =2\pi \,\,\,or\,\,\,2\pi v=2\pi \Rightarrow v=1Hz\] The sign inside the bracket is negative, hence the wave travels in + ve x- direction.
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