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JEE Main & Advanced Physics Wave Mechanics Question Bank Self Evaluation Test - Waves

  • question_answer
    At t=0, the shape of a travelling pulse is given by \[y(x,0)=\frac{4\times {{10}^{-3}}}{8\times {{(x)}^{-2}}}\] where x and y are in metres. The wave function for the travelling pulse if the velocity or propagation is 5 m/s in the x direction is given by

    A)  \[y(x,t)=\frac{4\times {{10}^{-3}}}{8-({{x}^{2}}-5t)}\]

    B)  \[y(x,t)=\frac{4\times {{10}^{-3}}}{8-{{(x-5t)}^{2}}}\]

    C) \[y(x,t)=\frac{4\times {{10}^{-3}}}{8-{{(x+5t)}^{2}}}\]

    D) \[y(x,t)=\frac{4\times {{10}^{-3}}}{8-({{x}^{2}}+5t)}\]

    Correct Answer: B

    Solution :

    [b] \[y(x,t)=f(x-vt)\] \[y=(x,0)=\frac{4\times {{10}^{-3}}}{8-{{x}^{2}}}\] For a travelling wave in the x-direction \[y(x,t)=\frac{4\times {{10}^{-3}}}{8-{{(x-5t)}^{2}}}\]


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