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JEE Main & Advanced Physics Wave Mechanics Question Bank Self Evaluation Test - Waves

  • question_answer
    Two waves are represented by the equations \[{{y}_{1}}=a\sin (\omega t+kx+0.57)m\] and \[{{y}_{2}}=a\cos \]\[(\omega t+kx)m\], where x is in meter and t in sec. The phase difference between them is

    A)  1.0 radian       

    B)         1.25 radian

    C) 1.57 radian      

    D)        0.57 radian

    Correct Answer: A

    Solution :

    [a] Here, \[{{y}_{1}}=a\,\sin \,(\omega t+kx+0.57)\] and \[{{y}_{2}}=a\,\cos \,(\omega t+kx)\] \[=a\,\sin \left[ \frac{\pi }{2}+(\omega t+kx) \right]\] Phase difference, \[\Delta \phi ={{\phi }_{2}}={{\phi }_{1}}\] \[=\frac{\pi }{2}-0.57\] \[=\frac{3.14}{2}-0.57=1.57-0.57=1\,radian\]


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