A) \[f(x)=\sqrt{{{x}^{2}}},\] \[g(x)=x\]
B) \[f(x)={{\sin }^{2}}x+{{\cos }^{2}}x;\,g(x)=1\]
C) \[f(x)=\frac{x}{x},\,\,g(x)=1\]
D) None of these
Correct Answer: B
Solution :
For checking equal function Domain of \[f(x)=R\] but range\[=[0,\infty )\] Domain of \[g(x)=R,\]range =R Domain same but range is different so it is not an equal function. Domain of \[f(x)=R\] Domain of \[g(x)=R\] Domain and range both same so it is an equal function. Domain of \[f(x)=R-\left\{ 0 \right\}\] Domain of \[g(x)=R\] Not equal function as domain is different.
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