A) \[x=\pm 1\]
B) All real values of x
C) \[-1<x<1\]
D) \[x>1\]and \[x<-1\]
Correct Answer: A
Solution :
Given: \[2\sin \theta =x+\frac{1}{x}\] We know that \[-1\le \sin \theta <1,\] \[-2\le 2\sin \theta <2\] So, \[-2\le x+\frac{1}{x}<2\] Thus, the given equation is valid only if \[x=\pm 1\]
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