A) 0
B) 1
C) 2
D) 3
Correct Answer: B
Solution :
\[{{\sin }^{2}}(3\pi )+co{{s}^{2}}(4\pi )+{{\tan }^{2}}(5\pi )\] \[={{\sin }^{2}}(3\pi )+{{\cos }^{2}}(\pi +3\pi )+{{\tan }^{2}}(5\pi )\] \[=({{\sin }^{2}}(3\pi )+{{\cos }^{2}}(3\pi )+{{\tan }^{2}}(2\times 2\pi +\pi )\] \[=1+{{\tan }^{2}}\pi ={{\sec }^{2}}\pi =1\]
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