A) \[2(1-\cos A)(1+\sin A)\]
B) \[2(1-sinA)(1+\cos A)\]
C) \[2(1-cos\,A)(1-sinA)\]
D) None of the above
Correct Answer: B
Solution :
\[{{(1-\sin A+\cos A)}^{2}}\] \[=1+{{\sin }^{2}}A+{{\cos }^{2}}A-2\sin A\]\[-2\sin A.\cos A+2\cos A\] \[=2-2\sin A-2\sin A\cos A+2\cos A\] \[=2(1-\sin A)+2\cos A(1-\sin A)\] \[=2(1+\cos A)(1-\sin A)\]
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