JEE Main & Advanced Mathematics Three Dimensional Geometry Question Bank Self Evaluation Test - Three Dimensional Geometry

  • question_answer
    The equation of a sphere is \[{{x}^{2}}+{{y}^{2}}+{{z}^{2}}-10z=0\]. If one end point of a diameter of the sphere is (-3, -4, 5), what is the other end point?

    A) \[(-3,-4,-5)\]

    B) \[(3,4,5)\]

    C) \[(3,4,-5)\]

    D) \[(-3,4,-5)\]

    Correct Answer: B

    Solution :

    [b] The equation of the given sphere is \[{{x}^{2}}+{{y}^{2}}+{{z}^{2}}-10z=0.\] \[\therefore \] Its centre is (0, 0, 5). Coordinates of one end point of a diameter of the sphere is given as (-3, -4, 5). Let coordinates of another end point of this diameter \[({{x}_{1}},{{y}_{1}},{{z}_{1}})\] \[\therefore \frac{-3+{{x}_{1}}}{2}=0\Rightarrow {{x}_{1}}=3\] \[\frac{-4+{{y}_{1}}}{2}=0\Rightarrow {{y}_{1}}=4\] and \[\frac{5+{{z}_{1}}}{2}=5\,\,\,\,\,\,\,\Rightarrow {{z}_{1}}=5\] \[\therefore \] Required coordinates are (3, 4, 5).


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