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JEE Main & Advanced Mathematics Three Dimensional Geometry Question Bank Self Evaluation Test - Three Dimensional Geometry

  • question_answer
    The equation of the plane through (1, 1, 1) and passing through the line of intersection of the planes \[x+2y-z+1=0\] and \[3x-y-4z+3=0\]is

    A) \[8x+5y-11z+8=0\]

    B) \[8x+5y-11z+8=0\]

    C) \[8x-5y-11z+8=0\]

    D) None of these

    Correct Answer: C

    Solution :

    [c] Any plane through the line is \[(x+2y-z+1)+\lambda (3x-y-4z+3)=0.\] It passes through \[(1,1,1).\] \[\therefore \] \[(1+2-1+1)+\lambda (3-1-4+3)=0\Rightarrow \lambda =-3\] Therefore. The required plane is \[8x-5y-11z+8=0.\]


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