JEE Main & Advanced Mathematics Three Dimensional Geometry Question Bank Self Evaluation Test - Three Dimensional Geometry

  • question_answer
    Equation of the plane through the mid-point of the line segment joining the points P(4, 5, -10) and Q(-1, 2, 1) and perpendicular to PQ is

    A) \[\vec{r}.\left( \frac{3}{2}\hat{i}+\frac{7}{2}\hat{j}-\frac{9}{2}\hat{k} \right)=45\]

    B) \[\vec{r}.\left( -\hat{i}+2\hat{j}-\hat{k} \right)=\frac{135}{2}\]

    C) \[\vec{r}.(5\hat{i}+3\hat{j}-11\hat{k})+\frac{135}{2}=0\]

    D) \[\vec{r}.(5\hat{i}+3\hat{j}-11\hat{k})=\frac{135}{2}\]

    Correct Answer: D

    Solution :

    [d] Mid-point of PQ is \[=\left( \frac{3}{2},\frac{7}{2},\frac{-9}{2} \right)\] DR of the normal is \[=(4-(-1),5-2,-10-1)\] \[=5,3,-11\] \[\therefore \] Eqn. of plane is \[5\left( x-\frac{3}{2} \right)+3\left( y-\frac{7}{2} \right)-11\left( z+\frac{9}{2} \right)=0\] \[\Rightarrow 5x+3y-11z=\frac{135}{2}\] \[\Rightarrow \,\,r.\,(5\hat{j}+3\hat{j}-11\hat{k})=\frac{135}{2}\]


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