JEE Main & Advanced Mathematics Three Dimensional Geometry Question Bank Self Evaluation Test - Three Dimensional Geometry

  • question_answer
    If Q is the image of the point P(2, 3, 4) under the reflection in the plane \[x-2y+5z=6\], then the equation of the line \[PQ\]is

    A) \[\frac{x-2}{-1}=\frac{y-3}{2}=\frac{z-4}{5}\]

    B) \[\frac{x-2}{1}=\frac{y-3}{-2}=\frac{z-4}{5}\]

    C) \[\frac{x-2}{-1}=\frac{y-3}{-2}=\frac{z-4}{5}\]

    D) \[\frac{x-2}{1}=\frac{y-3}{2}=\frac{z-4}{5}\]

    Correct Answer: B

    Solution :

    [b] Let Q be the image of the point \[P(2,3,4)\] in the plane \[x-2y+5z=6,\] then PQ is normal to the plane \[\therefore \] Direction ratios of PQ are <1,-2, 5> Since PQ passes through P (2, 3, 4) and has direction ratios 1, -2, 5 \[\therefore \] Equation of PQ is \[\frac{(x-2)}{1}=\frac{y-3}{-2}=\frac{z-4}{5}\]


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