JEE Main & Advanced Mathematics Three Dimensional Geometry Question Bank Self Evaluation Test - Three Dimensional Geometry

  • question_answer
    The angle between the line \[\frac{x-2}{a}=\frac{y-2}{b}=\frac{z-2}{c}\] and the plane \[ax+by+cz+6=0\] is

    A) \[{{\sin }^{-1}}\left( \frac{1}{\sqrt{{{a}^{2}}+{{b}^{2}}+{{c}^{2}}}} \right)\]

    B) \[45{}^\circ \]

    C) \[60{}^\circ \]

    D) \[90{}^\circ \]

    Correct Answer: D

    Solution :

    [d] Obviously the line perpendicular to the plane because \[\frac{a}{a}=\frac{b}{b}=\frac{c}{c}\] i.e., their direction ratios are proportional.


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